What are the solutions to the equation -7x+x^2-170=0 ?

The solutions to the equation -7x+x^2-170=0 are x=17,x=-10

Find the zeros of -7x+x^2-170=0

The zeros of -7x+x^2-170=0 are x=17,x=-10

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- 7 x + x^{2} - 170 = 0

x = 17, x = - 10

Solution steps

- 7 x + x^{2} - 170 = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 7 x - 170 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 170 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 170) = 27

x_{1, 2} = \frac{- ( - 7 ) \pm 27}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 27}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 27}{2 \cdot 1}

x = \frac{- ( - 7 ) + 27}{2 \cdot 1} : 17

x = \frac{- ( - 7 ) - 27}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = 17, x = - 10

x^{2} - 2 x + 46 = 0

b^{2} + 2 b + 43 = 0

x, x^{2} = 3 x + 10

3 x^{2} - 8 x - 21 = 0

9 - 3 x^{2} + 5 x - 8 + 7 x^{2} = 5 x^{2} - 9 + 4 x + 4 x

What are the solutions to the equation -7x+x^2-170=0 ?
The solutions to the equation -7x+x^2-170=0 are x=17,x=-10
Find the zeros of -7x+x^2-170=0
The zeros of -7x+x^2-170=0 are x=17,x=-10