What are the solutions to the equation 4x^2-15x+16=3x^2-7x ?

The solutions to the equation 4x^2-15x+16=3x^2-7x are x=4

Find the zeros of 4x^2-15x+16=3x^2-7x

The zeros of 4x^2-15x+16=3x^2-7x are x=4

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4 x^{2} - 15 x + 16 = 3 x^{2} - 7 x

x = 4

Solution steps

4 x^{2} - 15 x + 16 = 3 x^{2} - 7 x

Move

7 x

to the left side

4 x^{2} - 8 x + 16 = 3 x^{2}

Move

3 x^{2}

to the left side

x^{2} - 8 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 16 = 0

x_{1, 2} = \frac{- ( - 8 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 8 )}{2 \cdot 1}

\frac{- ( - 8 )}{2 \cdot 1} = 4

x = 4

The solution to the quadratic equation is:

x = 4

4 (x - 6)^{2} = 48

0 = x^{2} - 2 x - 7

- 4 x^{2} + 6 x + 4 = 0

2 x (x + 1) - 4 (x + 4) = 8

9 x^{2} - 256 = 0

What are the solutions to the equation 4x^2-15x+16=3x^2-7x ?
The solutions to the equation 4x^2-15x+16=3x^2-7x are x=4
Find the zeros of 4x^2-15x+16=3x^2-7x
The zeros of 4x^2-15x+16=3x^2-7x are x=4