What are the solutions to the equation (-3x^2-16x)/(12)+7=0 ?

The solutions to the equation (-3x^2-16x)/(12)+7=0 are x=-(2(4+sqrt(79)))/3 ,x=(2(sqrt(79)-4))/3

Find the zeros of (-3x^2-16x)/(12)+7=0

The zeros of (-3x^2-16x)/(12)+7=0 are x=-(2(4+sqrt(79)))/3 ,x=(2(sqrt(79)-4))/3

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\frac{- 3 x ^{2} - 16 x}{12} + 7 = 0

x = - \frac{2 ( 4 + 79 )}{3}, x = \frac{2 ( 79 - 4 )}{3}

Decimal Notation

x = - 8.59212 \dots, x = 3.25879 \dots

Solution steps

\frac{- 3 x ^{2} - 16 x}{12} + 7 = 0

Multiply both sides by

12

- 3 x^{2} - 16 x + 84 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 ( - 3 ) \cdot 84}{2 ( - 3 )}

(- 16)^{2} - 4 (- 3) \cdot 84 = 479

x_{1, 2} = \frac{- ( - 16 ) \pm 4 79}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 4 79}{2 ( - 3 )}, x_{2} = \frac{- ( - 16 ) - 4 79}{2 ( - 3 )}

x = \frac{- ( - 16 ) + 4 79}{2 ( - 3 )} : - \frac{2 ( 4 + 79 )}{3}

x = \frac{- ( - 16 ) - 4 79}{2 ( - 3 )} : \frac{2 ( 79 - 4 )}{3}

The solutions to the quadratic equation are:

x = - \frac{2 ( 4 + 79 )}{3}, x = \frac{2 ( 79 - 4 )}{3}

3 x^{2} + 16 x = 0

2 m^{2} + 13 m + 20 = 0

2 x^{2} - \frac{1}{2} = 0

- 4 x^{2} + 6 x - 16 = - 5 x^{2}

x^{2} - 10 x + 27

What are the solutions to the equation (-3x^2-16x)/(12)+7=0 ?
The solutions to the equation (-3x^2-16x)/(12)+7=0 are x=-(2(4+sqrt(79)))/3 ,x=(2(sqrt(79)-4))/3
Find the zeros of (-3x^2-16x)/(12)+7=0
The zeros of (-3x^2-16x)/(12)+7=0 are x=-(2(4+sqrt(79)))/3 ,x=(2(sqrt(79)-4))/3