What are the solutions to the equation 9x^2-4x=2 ?

The solutions to the equation 9x^2-4x=2 are x=(2+sqrt(22))/9 ,x=(2-sqrt(22))/9

Find the zeros of 9x^2-4x=2

The zeros of 9x^2-4x=2 are x=(2+sqrt(22))/9 ,x=(2-sqrt(22))/9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9 x^{2} - 4 x = 2

x = \frac{2 + 22}{9}, x = \frac{2 - 22}{9}

Decimal Notation

x = 0.74337 \dots, x = - 0.29893 \dots

Solution steps

9 x^{2} - 4 x = 2

Move

2

to the left side

9 x^{2} - 4 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 9 ( - 2 )}{2 \cdot 9}

(- 4)^{2} - 4 \cdot 9 (- 2) = 222

x_{1, 2} = \frac{- ( - 4 ) \pm 2 22}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 22}{2 \cdot 9}, x_{2} = \frac{- ( - 4 ) - 2 22}{2 \cdot 9}

x = \frac{- ( - 4 ) + 2 22}{2 \cdot 9} : \frac{2 + 22}{9}

x = \frac{- ( - 4 ) - 2 22}{2 \cdot 9} : \frac{2 - 22}{9}

The solutions to the quadratic equation are:

x = \frac{2 + 22}{9}, x = \frac{2 - 22}{9}

x, x^{2} + 4 y^{2} = - \frac{2}{5} x - \frac{4}{5} y + 4

2 4^{2} + x^{2} = 2 6^{2}

u^{2} + 2 u - 15 = 0

x^{2} + x - 780 = 0

x^{2} + (- \frac{11}{6})^{2} = 1^{2}

What are the solutions to the equation 9x^2-4x=2 ?
The solutions to the equation 9x^2-4x=2 are x=(2+sqrt(22))/9 ,x=(2-sqrt(22))/9
Find the zeros of 9x^2-4x=2
The zeros of 9x^2-4x=2 are x=(2+sqrt(22))/9 ,x=(2-sqrt(22))/9