What are the solutions to the equation x^2+(-(sqrt(11))/6)^2=1^2 ?

The solutions to the equation x^2+(-(sqrt(11))/6)^2=1^2 are x= 5/6 ,x=-5/6

Find the zeros of x^2+(-(sqrt(11))/6)^2=1^2

The zeros of x^2+(-(sqrt(11))/6)^2=1^2 are x= 5/6 ,x=-5/6

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x^{2} + (- \frac{11}{6})^{2} = 1^{2}

x = \frac{5}{6}, x = - \frac{5}{6}

Decimal Notation

x = 0.83333 \dots, x = - 0.83333 \dots

Solution steps

x^{2} + (- \frac{11}{6})^{2} = 1^{2}

Expand

x^{2} + (- \frac{11}{6})^{2} : x^{2} + \frac{11}{36}

Expand

1^{2} : 1

x^{2} + \frac{11}{36} = 1

Move

\frac{11}{36}

to the right side

x^{2} = 1 - \frac{11}{36}

Simplify

1 - \frac{11}{36} : \frac{25}{36}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{25}{36}, x = - \frac{25}{36}

\frac{25}{36} = \frac{5}{6}

- \frac{25}{36} = - \frac{5}{6}

x = \frac{5}{6}, x = - \frac{5}{6}

q^{2} + 4 q - 5 = 0

x, x^{2} + 4 x y + 16 y^{2} = 27

16 x^{2} - 4 x + 5 = 0

(x - 5)^{2} - 80 = 0

(x + 6)^{2} = - 4

What are the solutions to the equation x^2+(-(sqrt(11))/6)^2=1^2 ?
The solutions to the equation x^2+(-(sqrt(11))/6)^2=1^2 are x= 5/6 ,x=-5/6
Find the zeros of x^2+(-(sqrt(11))/6)^2=1^2
The zeros of x^2+(-(sqrt(11))/6)^2=1^2 are x= 5/6 ,x=-5/6