What are the solutions to the equation x^2+x-780=0 ?

The solutions to the equation x^2+x-780=0 are x=(-1+sqrt(3121))/2 ,x=(-1-sqrt(3121))/2

Find the zeros of x^2+x-780=0

The zeros of x^2+x-780=0 are x=(-1+sqrt(3121))/2 ,x=(-1-sqrt(3121))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + x - 780 = 0

x = \frac{- 1 + 3121}{2}, x = \frac{- 1 - 3121}{2}

Decimal Notation

x = 27.43295 \dots, x = - 28.43295 \dots

Solution steps

x^{2} + x - 780 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 780 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 780) = 3121

x_{1, 2} = \frac{- 1 \pm 3121}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 3121}{2 \cdot 1}, x_{2} = \frac{- 1 - 3121}{2 \cdot 1}

x = \frac{- 1 + 3121}{2 \cdot 1} : \frac{- 1 + 3121}{2}

x = \frac{- 1 - 3121}{2 \cdot 1} : \frac{- 1 - 3121}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 3121}{2}, x = \frac{- 1 - 3121}{2}

x^{2} + (- \frac{11}{6})^{2} = 1^{2}

q^{2} + 4 q - 5 = 0

x, x^{2} + 4 x y + 16 y^{2} = 27

16 x^{2} - 4 x + 5 = 0

(x - 5)^{2} - 80 = 0

What are the solutions to the equation x^2+x-780=0 ?
The solutions to the equation x^2+x-780=0 are x=(-1+sqrt(3121))/2 ,x=(-1-sqrt(3121))/2
Find the zeros of x^2+x-780=0
The zeros of x^2+x-780=0 are x=(-1+sqrt(3121))/2 ,x=(-1-sqrt(3121))/2