What are the solutions to the equation 2x^2-12x+7=0 ?

The solutions to the equation 2x^2-12x+7=0 are x=(6+sqrt(22))/2 ,x=(6-sqrt(22))/2

Find the zeros of 2x^2-12x+7=0

The zeros of 2x^2-12x+7=0 are x=(6+sqrt(22))/2 ,x=(6-sqrt(22))/2

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2 x^{2} - 12 x + 7 = 0

x = \frac{6 + 22}{2}, x = \frac{6 - 22}{2}

Decimal Notation

x = 5.34520 \dots, x = 0.65479 \dots

Solution steps

2 x^{2} - 12 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 2 \cdot 7}{2 \cdot 2}

(- 12)^{2} - 4 \cdot 2 \cdot 7 = 222

x_{1, 2} = \frac{- ( - 12 ) \pm 2 22}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 22}{2 \cdot 2}, x_{2} = \frac{- ( - 12 ) - 2 22}{2 \cdot 2}

x = \frac{- ( - 12 ) + 2 22}{2 \cdot 2} : \frac{6 + 22}{2}

x = \frac{- ( - 12 ) - 2 22}{2 \cdot 2} : \frac{6 - 22}{2}

The solutions to the quadratic equation are:

x = \frac{6 + 22}{2}, x = \frac{6 - 22}{2}

a x^{2} = b x

y^{2} = 4 - 3 y^{2}

x (x + 7) = 1 + 7 x

x^{2} + 16 = - 12 x

4 x^{2} - 6 x - 18 = 0

What are the solutions to the equation 2x^2-12x+7=0 ?
The solutions to the equation 2x^2-12x+7=0 are x=(6+sqrt(22))/2 ,x=(6-sqrt(22))/2
Find the zeros of 2x^2-12x+7=0
The zeros of 2x^2-12x+7=0 are x=(6+sqrt(22))/2 ,x=(6-sqrt(22))/2