What are the solutions to the equation k^2-11=89-k^2 ?

The solutions to the equation k^2-11=89-k^2 are k=5sqrt(2),k=-5sqrt(2)

Find the zeros of k^2-11=89-k^2

The zeros of k^2-11=89-k^2 are k=5sqrt(2),k=-5sqrt(2)

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k^{2} - 11 = 89 - k^{2}

k = 52, k = - 52

Decimal Notation

k = 7.07106 \dots, k = - 7.07106 \dots

Solution steps

k^{2} - 11 = 89 - k^{2}

Move

11

to the right side

k^{2} = - k^{2} + 100

Move

k^{2}

to the left side

2 k^{2} = 100

Divide both sides by

2

k^{2} = 50

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

k = 50, k = - 50

50 = 52

- 50 = - 52

k = 52, k = - 52

12 x^{2} - 48 x - 5 = 0

x^{2} + 4 x + 8 = 0

3 x^{2} - 48 x + 144 = 0

2 x^{2} - 4 x = 0

x^{2} + 12 x + c

What are the solutions to the equation k^2-11=89-k^2 ?
The solutions to the equation k^2-11=89-k^2 are k=5sqrt(2),k=-5sqrt(2)
Find the zeros of k^2-11=89-k^2
The zeros of k^2-11=89-k^2 are k=5sqrt(2),k=-5sqrt(2)