What are the solutions to the equation 6x^2+4x-5=0 ?

The solutions to the equation 6x^2+4x-5=0 are x=(-2+sqrt(34))/6 ,x=-(2+sqrt(34))/6

Find the zeros of 6x^2+4x-5=0

The zeros of 6x^2+4x-5=0 are x=(-2+sqrt(34))/6 ,x=-(2+sqrt(34))/6

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6 x^{2} + 4 x - 5 = 0

x = \frac{- 2 + 34}{6}, x = - \frac{2 + 34}{6}

Decimal Notation

x = 0.63849 \dots, x = - 1.30515 \dots

Solution steps

6 x^{2} + 4 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 6 ( - 5 )}{2 \cdot 6}

4^{2} - 4 \cdot 6 (- 5) = 234

x_{1, 2} = \frac{- 4 \pm 2 34}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 4 + 2 34}{2 \cdot 6}, x_{2} = \frac{- 4 - 2 34}{2 \cdot 6}

x = \frac{- 4 + 2 34}{2 \cdot 6} : \frac{- 2 + 34}{6}

x = \frac{- 4 - 2 34}{2 \cdot 6} : - \frac{2 + 34}{6}

The solutions to the quadratic equation are:

x = \frac{- 2 + 34}{6}, x = - \frac{2 + 34}{6}

x^{2} + 15 x = 6 x

3 x^{2} - x = - 4

3 x^{2} - x = - 5

25 x^{2} - 20 x - 6 = 0

2 (x - 4)^{2} = 3

What are the solutions to the equation 6x^2+4x-5=0 ?
The solutions to the equation 6x^2+4x-5=0 are x=(-2+sqrt(34))/6 ,x=-(2+sqrt(34))/6
Find the zeros of 6x^2+4x-5=0
The zeros of 6x^2+4x-5=0 are x=(-2+sqrt(34))/6 ,x=-(2+sqrt(34))/6