What are the solutions to the equation 2(x-4)^2=3 ?

The solutions to the equation 2(x-4)^2=3 are x=sqrt(3/2)+4,x=-sqrt(3/2)+4

Find the zeros of 2(x-4)^2=3

The zeros of 2(x-4)^2=3 are x=sqrt(3/2)+4,x=-sqrt(3/2)+4

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2 (x - 4)^{2} = 3

x = \frac{3}{2} + 4, x = - \frac{3}{2} + 4

Decimal Notation

x = 5.22474 \dots, x = 2.77525 \dots

Solution steps

2 (x - 4)^{2} = 3

Divide both sides by

2

(x - 4)^{2} = \frac{3}{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = \frac{3}{2} : x = \frac{3}{2} + 4

Solve

x - 4 = - \frac{3}{2} : x = - \frac{3}{2} + 4

The solutions to the quadratic equation are:

x = \frac{3}{2} + 4, x = - \frac{3}{2} + 4

s, s^{2} + 2 s + 4 = 0

- 4 x^{2} - 8 x + 12 = 0

2 (x + 1)^{2} = 32

y^{2} - 2 y - 11 = 0

2 x^{2} + 30 = 0

What are the solutions to the equation 2(x-4)^2=3 ?
The solutions to the equation 2(x-4)^2=3 are x=sqrt(3/2)+4,x=-sqrt(3/2)+4
Find the zeros of 2(x-4)^2=3
The zeros of 2(x-4)^2=3 are x=sqrt(3/2)+4,x=-sqrt(3/2)+4