What are the solutions to the equation 3x^2-x=-5 ?

The solutions to the equation 3x^2-x=-5 are x= 1/6+i(sqrt(59))/6 ,x= 1/6-i(sqrt(59))/6

Find the zeros of 3x^2-x=-5

The zeros of 3x^2-x=-5 are x= 1/6+i(sqrt(59))/6 ,x= 1/6-i(sqrt(59))/6

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3 x^{2} - x = - 5

x = \frac{1}{6} + i \frac{59}{6}, x = \frac{1}{6} - i \frac{59}{6}

Solution steps

3 x^{2} - x = - 5

Move

5

to the left side

3 x^{2} - x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 3 \cdot 5}{2 \cdot 3}

Simplify

(- 1)^{2} - 4 \cdot 3 \cdot 5 : 59 i

x_{1, 2} = \frac{- ( - 1 ) \pm 59 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 59 i}{2 \cdot 3}, x_{2} = \frac{- ( - 1 ) - 59 i}{2 \cdot 3}

x = \frac{- ( - 1 ) + 59 i}{2 \cdot 3} : \frac{1}{6} + i \frac{59}{6}

x = \frac{- ( - 1 ) - 59 i}{2 \cdot 3} : \frac{1}{6} - i \frac{59}{6}

The solutions to the quadratic equation are:

x = \frac{1}{6} + i \frac{59}{6}, x = \frac{1}{6} - i \frac{59}{6}

25 x^{2} - 20 x - 6 = 0

2 (x - 4)^{2} = 3

s, s^{2} + 2 s + 4 = 0

- 4 x^{2} - 8 x + 12 = 0

2 (x + 1)^{2} = 32

What are the solutions to the equation 3x^2-x=-5 ?
The solutions to the equation 3x^2-x=-5 are x= 1/6+i(sqrt(59))/6 ,x= 1/6-i(sqrt(59))/6
Find the zeros of 3x^2-x=-5
The zeros of 3x^2-x=-5 are x= 1/6+i(sqrt(59))/6 ,x= 1/6-i(sqrt(59))/6