What are the solutions to the equation solvefor s,s^2+2s+4=0 ?

The solutions to the equation solvefor s,s^2+2s+4=0 are s=-1+sqrt(3)i,s=-1-sqrt(3)i

Find the zeros of solvefor s,s^2+2s+4=0

The zeros of solvefor s,s^2+2s+4=0 are s=-1+sqrt(3)i,s=-1-sqrt(3)i

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s, s^{2} + 2 s + 4 = 0

s = - 1 + 3 i, s = - 1 - 3 i

Solution steps

s^{2} + 2 s + 4 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 4 : 23 i

s_{1, 2} = \frac{- 2 \pm 2 3 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 2 + 2 3 i}{2 \cdot 1}, s_{2} = \frac{- 2 - 2 3 i}{2 \cdot 1}

s = \frac{- 2 + 2 3 i}{2 \cdot 1} : - 1 + 3 i

s = \frac{- 2 - 2 3 i}{2 \cdot 1} : - 1 - 3 i

The solutions to the quadratic equation are:

s = - 1 + 3 i, s = - 1 - 3 i

- 4 x^{2} - 8 x + 12 = 0

2 (x + 1)^{2} = 32

y^{2} - 2 y - 11 = 0

2 x^{2} + 30 = 0

16 (4 x - 1)^{2} = 25

What are the solutions to the equation solvefor s,s^2+2s+4=0 ?
The solutions to the equation solvefor s,s^2+2s+4=0 are s=-1+sqrt(3)i,s=-1-sqrt(3)i
Find the zeros of solvefor s,s^2+2s+4=0
The zeros of solvefor s,s^2+2s+4=0 are s=-1+sqrt(3)i,s=-1-sqrt(3)i