What are the solutions to the equation w^2-9w+14=0 ?

The solutions to the equation w^2-9w+14=0 are w=7,w=2

Find the zeros of w^2-9w+14=0

The zeros of w^2-9w+14=0 are w=7,w=2

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w^{2} - 9 w + 14 = 0

w = 7, w = 2

Solution steps

w^{2} - 9 w + 14 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 14}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 14 = 5

w_{1, 2} = \frac{- ( - 9 ) \pm 5}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 9 ) + 5}{2 \cdot 1}, w_{2} = \frac{- ( - 9 ) - 5}{2 \cdot 1}

w = \frac{- ( - 9 ) + 5}{2 \cdot 1} : 7

w = \frac{- ( - 9 ) - 5}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

w = 7, w = 2

15 x^{2} + 11 x + 2 = 0

y (y - 5) = 6

2 x^{2} = x^{2} + 7

(3 x - 1)^{2} - 13 = - 9

3 x^{2} + 7 x + 14 = - 7 x

What are the solutions to the equation w^2-9w+14=0 ?
The solutions to the equation w^2-9w+14=0 are w=7,w=2
Find the zeros of w^2-9w+14=0
The zeros of w^2-9w+14=0 are w=7,w=2