What are the solutions to the equation 2x^2=x^2+7 ?

The solutions to the equation 2x^2=x^2+7 are x=sqrt(7),x=-sqrt(7)

Find the zeros of 2x^2=x^2+7

The zeros of 2x^2=x^2+7 are x=sqrt(7),x=-sqrt(7)

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2 x^{2} = x^{2} + 7

x = 7, x = - 7

Decimal Notation

x = 2.64575 \dots, x = - 2.64575 \dots

Solution steps

2 x^{2} = x^{2} + 7

Move

x^{2}

to the left side

x^{2} = 7

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 7, x = - 7

(3 x - 1)^{2} - 13 = - 9

3 x^{2} + 7 x + 14 = - 7 x

2 x = (x + 2) (x - 1)

6 x^{2} + 31 x + 35 = 0

(a + 3) (a - 5) = 5

What are the solutions to the equation 2x^2=x^2+7 ?
The solutions to the equation 2x^2=x^2+7 are x=sqrt(7),x=-sqrt(7)
Find the zeros of 2x^2=x^2+7
The zeros of 2x^2=x^2+7 are x=sqrt(7),x=-sqrt(7)