What are the solutions to the equation j(x)=x^2 ?

The solutions to the equation j(x)=x^2 are x=j,x=0

Find the zeros of j(x)=x^2

The zeros of j(x)=x^2 are x=j,x=0

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j (x) = x^{2}

x = j, x = 0

Solution steps

j (x) = x^{2}

Refine

j x = x^{2}

Switch sides

x^{2} = j x

Move

j x

to the left side

x^{2} - j x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - j ) \pm ( - j ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

Simplify

(- j)^{2} - 4 \cdot 1 \cdot 0 : j

x_{1, 2} = \frac{- ( - j ) \pm j}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - j ) + j}{2 \cdot 1}, x_{2} = \frac{- ( - j ) - j}{2 \cdot 1}

x = \frac{- ( - j ) + j}{2 \cdot 1} : j

x = \frac{- ( - j ) - j}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = j, x = 0

2 x^{2} + 2 x = 6

2 x^{2} + 2 x = 3

x^{2} + 10 x + 70 = 0

2 x (2 x + 1) - 10 x - 16 = 5 x^{2}

9 z^{2} - 49 = 0

What are the solutions to the equation j(x)=x^2 ?
The solutions to the equation j(x)=x^2 are x=j,x=0
Find the zeros of j(x)=x^2
The zeros of j(x)=x^2 are x=j,x=0