What are the solutions to the equation 2x(2x+1)-10x-16=5x^2 ?

The solutions to the equation 2x(2x+1)-10x-16=5x^2 are x=-4

Find the zeros of 2x(2x+1)-10x-16=5x^2

The zeros of 2x(2x+1)-10x-16=5x^2 are x=-4

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2 x (2 x + 1) - 10 x - 16 = 5 x^{2}

x = - 4

Solution steps

2 x (2 x + 1) - 10 x - 16 = 5 x^{2}

Expand

2 x (2 x + 1) - 10 x - 16 : 4 x^{2} - 8 x - 16

4 x^{2} - 8 x - 16 = 5 x^{2}

Move

5 x^{2}

to the left side

- x^{2} - 8 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 ( - 1 ) ( - 16 )}{2 ( - 1 )}

(- 8)^{2} - 4 (- 1) (- 16) = 0

x_{1, 2} = \frac{- ( - 8 ) \pm 0}{2 ( - 1 )}

x = \frac{- ( - 8 )}{2 ( - 1 )}

\frac{- ( - 8 )}{2 ( - 1 )} = - 4

x = - 4

The solution to the quadratic equation is:

x = - 4

9 z^{2} - 49 = 0

9 x^{2} = 42 x - 50

(3 x + 1) (x + 5) = 0

5582.28 x^{2} + 81.42 x = 43200

x^{2} - 3 = 2 x - 4 x^{2} + 6

What are the solutions to the equation 2x(2x+1)-10x-16=5x^2 ?
The solutions to the equation 2x(2x+1)-10x-16=5x^2 are x=-4
Find the zeros of 2x(2x+1)-10x-16=5x^2
The zeros of 2x(2x+1)-10x-16=5x^2 are x=-4