What are the solutions to the equation 6x^2-28x+24=0 ?

The solutions to the equation 6x^2-28x+24=0 are x=(7+sqrt(13))/3 ,x=(7-sqrt(13))/3

Find the zeros of 6x^2-28x+24=0

The zeros of 6x^2-28x+24=0 are x=(7+sqrt(13))/3 ,x=(7-sqrt(13))/3

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6 x^{2} - 28 x + 24 = 0

x = \frac{7 + 13}{3}, x = \frac{7 - 13}{3}

Decimal Notation

x = 3.53518 \dots, x = 1.13148 \dots

Solution steps

6 x^{2} - 28 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 28 ) \pm ( - 28 ) ^{2} - 4 \cdot 6 \cdot 24}{2 \cdot 6}

(- 28)^{2} - 4 \cdot 6 \cdot 24 = 413

x_{1, 2} = \frac{- ( - 28 ) \pm 4 13}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 28 ) + 4 13}{2 \cdot 6}, x_{2} = \frac{- ( - 28 ) - 4 13}{2 \cdot 6}

x = \frac{- ( - 28 ) + 4 13}{2 \cdot 6} : \frac{7 + 13}{3}

x = \frac{- ( - 28 ) - 4 13}{2 \cdot 6} : \frac{7 - 13}{3}

The solutions to the quadratic equation are:

x = \frac{7 + 13}{3}, x = \frac{7 - 13}{3}

- 0.01 x^{2} + 50 x + 300 = 0

(x - 2) (3 x + 1) = 0

n^{2} - 11 n + 24 = 0

a = 6 a^{2}

0 = x^{2} - 11 x + 24

What are the solutions to the equation 6x^2-28x+24=0 ?
The solutions to the equation 6x^2-28x+24=0 are x=(7+sqrt(13))/3 ,x=(7-sqrt(13))/3
Find the zeros of 6x^2-28x+24=0
The zeros of 6x^2-28x+24=0 are x=(7+sqrt(13))/3 ,x=(7-sqrt(13))/3