What are the solutions to the equation factor 12x-4-9x^2=0 ?

The solutions to the equation factor 12x-4-9x^2=0 are x= 2/3

Find the zeros of factor 12x-4-9x^2=0

The zeros of factor 12x-4-9x^2=0 are x= 2/3

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12 x - 4 - 9 x^{2} = 0

x = \frac{2}{3}

Decimal Notation

x = 0.66666 \dots

Solution steps

12 x - 4 - 9 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 9 x^{2} + 12 x - 4 = 0

Factor

- 9 x^{2} + 12 x - 4 : - (3 x - 2)^{2}

- (3 x - 2)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 2 = 0

Solve

3 x - 2 = 0 : x = \frac{2}{3}

The solution to the quadratic equation is:

x = \frac{2}{3}

b, A = \frac{1}{3} b^{2} c

- 8 x + 30 = - 3 x^{2} + 5 x

(4 - r) (- 4 - r) + 16 = 0

c^{2} - 5 c + 3 = 0

(z^{2} + 1) = 0

What are the solutions to the equation factor 12x-4-9x^2=0 ?
The solutions to the equation factor 12x-4-9x^2=0 are x= 2/3
Find the zeros of factor 12x-4-9x^2=0
The zeros of factor 12x-4-9x^2=0 are x= 2/3