What are the solutions to the equation (z^2+1)=0 ?

The solutions to the equation (z^2+1)=0 are z=i,z=-i

Find the zeros of (z^2+1)=0

The zeros of (z^2+1)=0 are z=i,z=-i

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(z^{2} + 1) = 0

z = i, z = - i

Solution steps

(z^{2} + 1) = 0

z^{2} + 1 = 0

Move

1

to the right side

z^{2} = - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

z = - 1, z = - - 1

- 1 = i

- - 1 = - i

z = i, z = - i

3 x^{2} + 18 x - 45 = 0

x^{2} + 18 x + 92 = 0

7 x^{2} + 21 x = 28

x^{2} + 100 = 29 x

y^{2} + 3 y = 6 y + 10

What are the solutions to the equation (z^2+1)=0 ?
The solutions to the equation (z^2+1)=0 are z=i,z=-i
Find the zeros of (z^2+1)=0
The zeros of (z^2+1)=0 are z=i,z=-i