What are the solutions to the equation -8x+30=-3x^2+5x ?

The solutions to the equation -8x+30=-3x^2+5x are x= 13/6-i(sqrt(191))/6 ,x= 13/6+i(sqrt(191))/6

Find the zeros of -8x+30=-3x^2+5x

The zeros of -8x+30=-3x^2+5x are x= 13/6-i(sqrt(191))/6 ,x= 13/6+i(sqrt(191))/6

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- 8 x + 30 = - 3 x^{2} + 5 x

x = \frac{13}{6} - i \frac{191}{6}, x = \frac{13}{6} + i \frac{191}{6}

Solution steps

- 8 x + 30 = - 3 x^{2} + 5 x

Switch sides

- 3 x^{2} + 5 x = - 8 x + 30

Move

30

to the left side

- 3 x^{2} + 5 x - 30 = - 8 x

Move

8 x

to the left side

- 3 x^{2} + 13 x - 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 ( - 3 ) ( - 30 )}{2 ( - 3 )}

Simplify

1 3^{2} - 4 (- 3) (- 30) : 191 i

x_{1, 2} = \frac{- 13 \pm 191 i}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 13 + 191 i}{2 ( - 3 )}, x_{2} = \frac{- 13 - 191 i}{2 ( - 3 )}

x = \frac{- 13 + 191 i}{2 ( - 3 )} : \frac{13}{6} - i \frac{191}{6}

x = \frac{- 13 - 191 i}{2 ( - 3 )} : \frac{13}{6} + i \frac{191}{6}

The solutions to the quadratic equation are:

x = \frac{13}{6} - i \frac{191}{6}, x = \frac{13}{6} + i \frac{191}{6}

(4 - r) (- 4 - r) + 16 = 0

c^{2} - 5 c + 3 = 0

(z^{2} + 1) = 0

3 x^{2} + 18 x - 45 = 0

x^{2} + 18 x + 92 = 0

What are the solutions to the equation -8x+30=-3x^2+5x ?
The solutions to the equation -8x+30=-3x^2+5x are x= 13/6-i(sqrt(191))/6 ,x= 13/6+i(sqrt(191))/6
Find the zeros of -8x+30=-3x^2+5x
The zeros of -8x+30=-3x^2+5x are x= 13/6-i(sqrt(191))/6 ,x= 13/6+i(sqrt(191))/6