What are the solutions to the equation x^2+18x+92=0 ?

The solutions to the equation x^2+18x+92=0 are x=-9+sqrt(11)i,x=-9-sqrt(11)i

Find the zeros of x^2+18x+92=0

The zeros of x^2+18x+92=0 are x=-9+sqrt(11)i,x=-9-sqrt(11)i

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x^{2} + 18 x + 92 = 0

x = - 9 + 11 i, x = - 9 - 11 i

Solution steps

x^{2} + 18 x + 92 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 92}{2 \cdot 1}

Simplify

1 8^{2} - 4 \cdot 1 \cdot 92 : 211 i

x_{1, 2} = \frac{- 18 \pm 2 11 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 18 + 2 11 i}{2 \cdot 1}, x_{2} = \frac{- 18 - 2 11 i}{2 \cdot 1}

x = \frac{- 18 + 2 11 i}{2 \cdot 1} : - 9 + 11 i

x = \frac{- 18 - 2 11 i}{2 \cdot 1} : - 9 - 11 i

The solutions to the quadratic equation are:

x = - 9 + 11 i, x = - 9 - 11 i

7 x^{2} + 21 x = 28

x^{2} + 100 = 29 x

y^{2} + 3 y = 6 y + 10

4 x^{2} + 6 x + 8 = 0

3 x^{2} - 6 x = 5

What are the solutions to the equation x^2+18x+92=0 ?
The solutions to the equation x^2+18x+92=0 are x=-9+sqrt(11)i,x=-9-sqrt(11)i
Find the zeros of x^2+18x+92=0
The zeros of x^2+18x+92=0 are x=-9+sqrt(11)i,x=-9-sqrt(11)i