What are the solutions to the equation solvefor x,x^2-7x+12=0 ?

The solutions to the equation solvefor x,x^2-7x+12=0 are x=4,x=3

Find the zeros of solvefor x,x^2-7x+12=0

The zeros of solvefor x,x^2-7x+12=0 are x=4,x=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x, x^{2} - 7 x + 12 = 0

x = 4, x = 3

Solution steps

x^{2} - 7 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 12 = 1

x_{1, 2} = \frac{- ( - 7 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 1}{2 \cdot 1}

x = \frac{- ( - 7 ) + 1}{2 \cdot 1} : 4

x = \frac{- ( - 7 ) - 1}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 4, x = 3

36 - 25 x^{2} = 0

x (x + 2) = 143

9 x^{2} + 24 x + 19 = 0

4 x^{2} + 10 x - 3 = 0

t, d = 4.9 t^{2}

What are the solutions to the equation solvefor x,x^2-7x+12=0 ?
The solutions to the equation solvefor x,x^2-7x+12=0 are x=4,x=3
Find the zeros of solvefor x,x^2-7x+12=0
The zeros of solvefor x,x^2-7x+12=0 are x=4,x=3