What are the solutions to the equation 36-25x^2=0 ?

The solutions to the equation 36-25x^2=0 are x= 6/5 ,x=-6/5

Find the zeros of 36-25x^2=0

The zeros of 36-25x^2=0 are x= 6/5 ,x=-6/5

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36 - 25 x^{2} = 0

x = \frac{6}{5}, x = - \frac{6}{5}

Decimal Notation

x = 1.2, x = - 1.2

Solution steps

36 - 25 x^{2} = 0

Move

36

to the right side

- 25 x^{2} = - 36

Divide both sides by

- 25

x^{2} = \frac{36}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{36}{25}, x = - \frac{36}{25}

\frac{36}{25} = \frac{6}{5}

- \frac{36}{25} = - \frac{6}{5}

x = \frac{6}{5}, x = - \frac{6}{5}

x (x + 2) = 143

9 x^{2} + 24 x + 19 = 0

4 x^{2} + 10 x - 3 = 0

t, d = 4.9 t^{2}

u^{2} - 6 u + 9 = 0

What are the solutions to the equation 36-25x^2=0 ?
The solutions to the equation 36-25x^2=0 are x= 6/5 ,x=-6/5
Find the zeros of 36-25x^2=0
The zeros of 36-25x^2=0 are x= 6/5 ,x=-6/5