What are the solutions to the equation 0=-2x^2+20x-50 ?

The solutions to the equation 0=-2x^2+20x-50 are x=5

Find the zeros of 0=-2x^2+20x-50

The zeros of 0=-2x^2+20x-50 are x=5

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0 = - 2 x^{2} + 20 x - 50

x = 5

Solution steps

0 = - 2 x^{2} + 20 x - 50

Switch sides

- 2 x^{2} + 20 x - 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 ( - 2 ) ( - 50 )}{2 ( - 2 )}

2 0^{2} - 4 (- 2) (- 50) = 0

x_{1, 2} = \frac{- 20 \pm 0}{2 ( - 2 )}

x = \frac{- 20}{2 ( - 2 )}

\frac{- 20}{2 ( - 2 )} = 5

x = 5

The solution to the quadratic equation is:

x = 5

x^{2} + 10 x + 25 = 49

\frac{7}{2} x^{2} + 3 x + \frac{8}{3}

27 - \frac{3}{4} x^{2} = 0

- 5 x - 2 = - 3 x^{2}

X^{2} + 8 X + 15 = 0

What are the solutions to the equation 0=-2x^2+20x-50 ?
The solutions to the equation 0=-2x^2+20x-50 are x=5
Find the zeros of 0=-2x^2+20x-50
The zeros of 0=-2x^2+20x-50 are x=5