What are the solutions to the equation x^2+20=-9x ?

The solutions to the equation x^2+20=-9x are x=-4,x=-5

Find the zeros of x^2+20=-9x

The zeros of x^2+20=-9x are x=-4,x=-5

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x^{2} + 20 = - 9 x

x = - 4, x = - 5

Solution steps

x^{2} + 20 = - 9 x

Move

9 x

to the left side

x^{2} + 20 + 9 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 9 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 20 = 1

x_{1, 2} = \frac{- 9 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 1}{2 \cdot 1}, x_{2} = \frac{- 9 - 1}{2 \cdot 1}

x = \frac{- 9 + 1}{2 \cdot 1} : - 4

x = \frac{- 9 - 1}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = - 4, x = - 5

2200 + 35 x + x^{2} = 130 x

6 p^{2} = 13 p - 5

(y - 1)^{2} = 0

(x - 3)^{2} = - 8

833.6 = - 0.6 q^{2} + 9.6 q + 450

What are the solutions to the equation x^2+20=-9x ?
The solutions to the equation x^2+20=-9x are x=-4,x=-5
Find the zeros of x^2+20=-9x
The zeros of x^2+20=-9x are x=-4,x=-5