What are the solutions to the equation 2s^2+12s=0 ?

The solutions to the equation 2s^2+12s=0 are s=0,s=-6

Find the zeros of 2s^2+12s=0

The zeros of 2s^2+12s=0 are s=0,s=-6

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2 s^{2} + 12 s = 0

s = 0, s = - 6

Solution steps

2 s^{2} + 12 s = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

1 2^{2} - 4 \cdot 2 \cdot 0 = 12

s_{1, 2} = \frac{- 12 \pm 12}{2 \cdot 2}

Separate the solutions

s_{1} = \frac{- 12 + 12}{2 \cdot 2}, s_{2} = \frac{- 12 - 12}{2 \cdot 2}

s = \frac{- 12 + 12}{2 \cdot 2} : 0

s = \frac{- 12 - 12}{2 \cdot 2} : - 6

The solutions to the quadratic equation are:

s = 0, s = - 6

4 x - 9 = x (2 - x)

(x + 2) (x - 2) - 3 x = 0

5 x^{2} + 6 = - 19 b + 2 b^{2}

x^{2} + 18 = 9

(4 m + 8) (m - 3) = 0

What are the solutions to the equation 2s^2+12s=0 ?
The solutions to the equation 2s^2+12s=0 are s=0,s=-6
Find the zeros of 2s^2+12s=0
The zeros of 2s^2+12s=0 are s=0,s=-6