What are the solutions to the equation (13x-7)^2=110 ?

The solutions to the equation (13x-7)^2=110 are x=(sqrt(110)+7)/(13),x=(-sqrt(110)+7)/(13)

Find the zeros of (13x-7)^2=110

The zeros of (13x-7)^2=110 are x=(sqrt(110)+7)/(13),x=(-sqrt(110)+7)/(13)

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(13 x - 7)^{2} = 110

x = \frac{110 + 7}{13}, x = \frac{- 110 + 7}{13}

Decimal Notation

x = 1.34523 \dots, x = - 0.26831 \dots

Solution steps

(13 x - 7)^{2} = 110

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

13 x - 7 = 110 : x = \frac{110 + 7}{13}

Solve

13 x - 7 = - 110 : x = \frac{- 110 + 7}{13}

The solutions to the quadratic equation are:

x = \frac{110 + 7}{13}, x = \frac{- 110 + 7}{13}

- 12 = (x + 1)^{2}

1 - 6 x - x^{2}

8 w^{2} + 10 w - 3 = 0

64 x^{2} = 81

(x - 5)^{2} = - 16

What are the solutions to the equation (13x-7)^2=110 ?
The solutions to the equation (13x-7)^2=110 are x=(sqrt(110)+7)/(13),x=(-sqrt(110)+7)/(13)
Find the zeros of (13x-7)^2=110
The zeros of (13x-7)^2=110 are x=(sqrt(110)+7)/(13),x=(-sqrt(110)+7)/(13)