What are the solutions to the equation -12=(x+1)^2 ?

The solutions to the equation -12=(x+1)^2 are x=2sqrt(3)i-1,x=-2sqrt(3)i-1

Find the zeros of -12=(x+1)^2

The zeros of -12=(x+1)^2 are x=2sqrt(3)i-1,x=-2sqrt(3)i-1

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- 12 = (x + 1)^{2}

x = 23 i - 1, x = - 23 i - 1

Solution steps

- 12 = (x + 1)^{2}

Switch sides

(x + 1)^{2} = - 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = - 12 : x = 23 i - 1

Solve

x + 1 = - - 12 : x = - 23 i - 1

The solutions to the quadratic equation are:

x = 23 i - 1, x = - 23 i - 1

1 - 6 x - x^{2}

8 w^{2} + 10 w - 3 = 0

64 x^{2} = 81

(x - 5)^{2} = - 16

989 - 264 x + 12 x^{2} = 0

What are the solutions to the equation -12=(x+1)^2 ?
The solutions to the equation -12=(x+1)^2 are x=2sqrt(3)i-1,x=-2sqrt(3)i-1
Find the zeros of -12=(x+1)^2
The zeros of -12=(x+1)^2 are x=2sqrt(3)i-1,x=-2sqrt(3)i-1