What are the solutions to the equation x^2+7=5 ?

The solutions to the equation x^2+7=5 are x=sqrt(2)i,x=-sqrt(2)i

Find the zeros of x^2+7=5

The zeros of x^2+7=5 are x=sqrt(2)i,x=-sqrt(2)i

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x^{2} + 7 = 5

x = 2 i, x = - 2 i

Solution steps

x^{2} + 7 = 5

Move

7

to the right side

x^{2} = - 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 2, x = - - 2

- 2 = 2 i

- - 2 = - 2 i

x = 2 i, x = - 2 i

(x - 0.6) (3 x - 1.4) = \frac{26}{150}

3 x^{2} - 6 x + 1 = 12

x^{2} - \frac{1}{2} x + \frac{1}{16} = 0

x^{2} - x - 32 = 0

4 - 4 x^{2} + 15 x = 0

What are the solutions to the equation x^2+7=5 ?
The solutions to the equation x^2+7=5 are x=sqrt(2)i,x=-sqrt(2)i
Find the zeros of x^2+7=5
The zeros of x^2+7=5 are x=sqrt(2)i,x=-sqrt(2)i