What are the solutions to the equation 4k(k+2)=2 ?

The solutions to the equation 4k(k+2)=2 are k=(-2+sqrt(6))/2 ,k=-(2+sqrt(6))/2

Find the zeros of 4k(k+2)=2

The zeros of 4k(k+2)=2 are k=(-2+sqrt(6))/2 ,k=-(2+sqrt(6))/2

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4 k (k + 2) = 2

k = \frac{- 2 + 6}{2}, k = - \frac{2 + 6}{2}

Decimal Notation

k = 0.22474 \dots, k = - 2.22474 \dots

Solution steps

4 k (k + 2) = 2

Expand

4 k (k + 2) : 4 k^{2} + 8 k

4 k^{2} + 8 k = 2

Move

2

to the left side

4 k^{2} + 8 k - 2 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 4 ( - 2 )}{2 \cdot 4}

8^{2} - 4 \cdot 4 (- 2) = 46

k_{1, 2} = \frac{- 8 \pm 4 6}{2 \cdot 4}

Separate the solutions

k_{1} = \frac{- 8 + 4 6}{2 \cdot 4}, k_{2} = \frac{- 8 - 4 6}{2 \cdot 4}

k = \frac{- 8 + 4 6}{2 \cdot 4} : \frac{- 2 + 6}{2}

k = \frac{- 8 - 4 6}{2 \cdot 4} : - \frac{2 + 6}{2}

The solutions to the quadratic equation are:

k = \frac{- 2 + 6}{2}, k = - \frac{2 + 6}{2}

(- x^{2} + 2 x + 1) = - 1 (x - 2 x - 1)

x (x - 4) = - 5

2 m^{2} = 15 + m

3 x^{2} + 5 x = - x - 9 + 2 x^{2}

2 4^{2} + 4 5^{2} = c^{2}

What are the solutions to the equation 4k(k+2)=2 ?
The solutions to the equation 4k(k+2)=2 are k=(-2+sqrt(6))/2 ,k=-(2+sqrt(6))/2
Find the zeros of 4k(k+2)=2
The zeros of 4k(k+2)=2 are k=(-2+sqrt(6))/2 ,k=-(2+sqrt(6))/2