What are the solutions to the equation 3x^2+5x=-x-9+2x^2 ?

The solutions to the equation 3x^2+5x=-x-9+2x^2 are x=-3

Find the zeros of 3x^2+5x=-x-9+2x^2

The zeros of 3x^2+5x=-x-9+2x^2 are x=-3

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3 x^{2} + 5 x = - x - 9 + 2 x^{2}

x = - 3

Solution steps

3 x^{2} + 5 x = - x - 9 + 2 x^{2}

Switch sides

- x - 9 + 2 x^{2} = 3 x^{2} + 5 x

Move

5 x

to the left side

2 x^{2} - 6 x - 9 = 3 x^{2}

Move

3 x^{2}

to the left side

- x^{2} - 6 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 1 ) ( - 9 )}{2 ( - 1 )}

(- 6)^{2} - 4 (- 1) (- 9) = 0

x_{1, 2} = \frac{- ( - 6 ) \pm 0}{2 ( - 1 )}

x = \frac{- ( - 6 )}{2 ( - 1 )}

\frac{- ( - 6 )}{2 ( - 1 )} = - 3

x = - 3

The solution to the quadratic equation is:

x = - 3

2 4^{2} + 4 5^{2} = c^{2}

7 t^{2} + 28 t + 56 = 0

9 x - 9 = - 4 x^{2}

x^{2} - 40 x + 144 = 0

x^{2} - 84 = - 3

What are the solutions to the equation 3x^2+5x=-x-9+2x^2 ?
The solutions to the equation 3x^2+5x=-x-9+2x^2 are x=-3
Find the zeros of 3x^2+5x=-x-9+2x^2
The zeros of 3x^2+5x=-x-9+2x^2 are x=-3