What are the solutions to the equation x^2+34x=0 ?

The solutions to the equation x^2+34x=0 are x=0,x=-34

Find the zeros of x^2+34x=0

The zeros of x^2+34x=0 are x=0,x=-34

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x^{2} + 34 x = 0

x = 0, x = - 34

Solution steps

x^{2} + 34 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 34 \pm 3 4 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

3 4^{2} - 4 \cdot 1 \cdot 0 = 34

x_{1, 2} = \frac{- 34 \pm 34}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 34 + 34}{2 \cdot 1}, x_{2} = \frac{- 34 - 34}{2 \cdot 1}

x = \frac{- 34 + 34}{2 \cdot 1} : 0

x = \frac{- 34 - 34}{2 \cdot 1} : - 34

The solutions to the quadratic equation are:

x = 0, x = - 34

(1 - x) (- 3 - x) + 5 = 0

x, 9 x^{2} - 4 y^{2} + 18 x - 16 y = 7

4 x^{2} + 34 x - 25 = 0

49 x^{2} - 7 x - \frac{3}{4}

5 x^{2} + 3 x + 7 = 0

What are the solutions to the equation x^2+34x=0 ?
The solutions to the equation x^2+34x=0 are x=0,x=-34
Find the zeros of x^2+34x=0
The zeros of x^2+34x=0 are x=0,x=-34