What are the solutions to the equation -5x^2-52x-63=0 ?

The solutions to the equation -5x^2-52x-63=0 are x=-9,x=-7/5

Find the zeros of -5x^2-52x-63=0

The zeros of -5x^2-52x-63=0 are x=-9,x=-7/5

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- 5 x^{2} - 52 x - 63 = 0

x = - 9, x = - \frac{7}{5}

Decimal Notation

x = - 9, x = - 1.4

Solution steps

- 5 x^{2} - 52 x - 63 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 52 ) \pm ( - 52 ) ^{2} - 4 ( - 5 ) ( - 63 )}{2 ( - 5 )}

(- 52)^{2} - 4 (- 5) (- 63) = 38

x_{1, 2} = \frac{- ( - 52 ) \pm 38}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- ( - 52 ) + 38}{2 ( - 5 )}, x_{2} = \frac{- ( - 52 ) - 38}{2 ( - 5 )}

x = \frac{- ( - 52 ) + 38}{2 ( - 5 )} : - 9

x = \frac{- ( - 52 ) - 38}{2 ( - 5 )} : - \frac{7}{5}

The solutions to the quadratic equation are:

x = - 9, x = - \frac{7}{5}

3 x^{2} - 6 x + 78 = 0

r^{2} + 2 r - 15 = 0

x^{2} + 14 x - 14 = 0

3 x^{2} - 22 x - 16 = 0

- (x - 3)^{2} - 7 = 0

What are the solutions to the equation -5x^2-52x-63=0 ?
The solutions to the equation -5x^2-52x-63=0 are x=-9,x=-7/5
Find the zeros of -5x^2-52x-63=0
The zeros of -5x^2-52x-63=0 are x=-9,x=-7/5