What are the solutions to the equation u^2-8=7u ?

The solutions to the equation u^2-8=7u are u=8,u=-1

Find the zeros of u^2-8=7u

The zeros of u^2-8=7u are u=8,u=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

u^{2} - 8 = 7 u

u = 8, u = - 1

Solution steps

u^{2} - 8 = 7 u

Move

7 u

to the left side

u^{2} - 8 - 7 u = 0

Write in the standard form

a x^{2} + b x + c = 0

u^{2} - 7 u - 8 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 8) = 9

u_{1, 2} = \frac{- ( - 7 ) \pm 9}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 7 ) + 9}{2 \cdot 1}, u_{2} = \frac{- ( - 7 ) - 9}{2 \cdot 1}

u = \frac{- ( - 7 ) + 9}{2 \cdot 1} : 8

u = \frac{- ( - 7 ) - 9}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

u = 8, u = - 1

4 x (1 - x) = x

x^{2} - 10 x - 20 = 0

x \frac{1}{4} x - \frac{3}{5} (x - 3) = 20

(d + 3)^{2} = 7

x^{2} - 2 x - \frac{1}{2} = 0

What are the solutions to the equation u^2-8=7u ?
The solutions to the equation u^2-8=7u are u=8,u=-1
Find the zeros of u^2-8=7u
The zeros of u^2-8=7u are u=8,u=-1