What are the solutions to the equation x^2-9=-2x ?

The solutions to the equation x^2-9=-2x are x=-1+sqrt(10),x=-1-sqrt(10)

Find the zeros of x^2-9=-2x

The zeros of x^2-9=-2x are x=-1+sqrt(10),x=-1-sqrt(10)

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x^{2} - 9 = - 2 x

x = - 1 + 10, x = - 1 - 10

Decimal Notation

x = 2.16227 \dots, x = - 4.16227 \dots

Solution steps

x^{2} - 9 = - 2 x

Move

2 x

to the left side

x^{2} - 9 + 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 2 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 9) = 210

x_{1, 2} = \frac{- 2 \pm 2 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 10}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 10}{2 \cdot 1}

x = \frac{- 2 + 2 10}{2 \cdot 1} : - 1 + 10

x = \frac{- 2 - 2 10}{2 \cdot 1} : - 1 - 10

The solutions to the quadratic equation are:

x = - 1 + 10, x = - 1 - 10

x^{2} - 9 = - 4 x

10 x - x^{2}

9 (x - 1)^{2} = 7

\frac{5}{6} x^{2} - \frac{2}{3} x = \frac{1}{3}

y, x^{3} + x^{2} y + y^{2} = 0

What are the solutions to the equation x^2-9=-2x ?
The solutions to the equation x^2-9=-2x are x=-1+sqrt(10),x=-1-sqrt(10)
Find the zeros of x^2-9=-2x
The zeros of x^2-9=-2x are x=-1+sqrt(10),x=-1-sqrt(10)