What are the solutions to the equation 3-12x^2=0 ?

The solutions to the equation 3-12x^2=0 are x= 1/2 ,x=-1/2

Find the zeros of 3-12x^2=0

The zeros of 3-12x^2=0 are x= 1/2 ,x=-1/2

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3 - 12 x^{2} = 0

x = \frac{1}{2}, x = - \frac{1}{2}

Decimal Notation

x = 0.5, x = - 0.5

Solution steps

3 - 12 x^{2} = 0

Move

3

to the right side

- 12 x^{2} = - 3

Divide both sides by

- 12

x^{2} = \frac{1}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{4}, x = - \frac{1}{4}

\frac{1}{4} = \frac{1}{2}

- \frac{1}{4} = - \frac{1}{2}

x = \frac{1}{2}, x = - \frac{1}{2}

x^{2} - 11 x + 9 = 0

- 16 t^{2} + 40 t = 0

1 6^{2} + 25 y^{2} - 400 = 0

x, x^{2} y^{3} - 2 x y = 6 x + y + 1

y, x^{4} + 2 y^{2} = 6 x^{2} + 4 y - 5

What are the solutions to the equation 3-12x^2=0 ?
The solutions to the equation 3-12x^2=0 are x= 1/2 ,x=-1/2
Find the zeros of 3-12x^2=0
The zeros of 3-12x^2=0 are x= 1/2 ,x=-1/2