What are the solutions to the equation 2x^2-7x=-5 ?

The solutions to the equation 2x^2-7x=-5 are x= 5/2 ,x=1

Find the zeros of 2x^2-7x=-5

The zeros of 2x^2-7x=-5 are x= 5/2 ,x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - 7 x = - 5

x = \frac{5}{2}, x = 1

Decimal Notation

x = 2.5, x = 1

Solution steps

2 x^{2} - 7 x = - 5

Move

5

to the left side

2 x^{2} - 7 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 \cdot 5}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 \cdot 5 = 3

x_{1, 2} = \frac{- ( - 7 ) \pm 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 3}{2 \cdot 2}, x_{2} = \frac{- ( - 7 ) - 3}{2 \cdot 2}

x = \frac{- ( - 7 ) + 3}{2 \cdot 2} : \frac{5}{2}

x = \frac{- ( - 7 ) - 3}{2 \cdot 2} : 1

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = 1

24 + 9 x = 10 - 4 x (x + 1)

d = \frac{a t ^{2}}{2}

- x^{2} + 5 x + 14 = 0

- 3 x^{2} - 36 x - 100

6 y + 10 = y^{2} + 3 y

What are the solutions to the equation 2x^2-7x=-5 ?
The solutions to the equation 2x^2-7x=-5 are x= 5/2 ,x=1
Find the zeros of 2x^2-7x=-5
The zeros of 2x^2-7x=-5 are x= 5/2 ,x=1