What are the solutions to the equation solvefor x,x^2+3x-5=0 ?

The solutions to the equation solvefor x,x^2+3x-5=0 are x=(-3+sqrt(29))/2 ,x=(-3-sqrt(29))/2

Find the zeros of solvefor x,x^2+3x-5=0

The zeros of solvefor x,x^2+3x-5=0 are x=(-3+sqrt(29))/2 ,x=(-3-sqrt(29))/2

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x, x^{2} + 3 x - 5 = 0

x = \frac{- 3 + 29}{2}, x = \frac{- 3 - 29}{2}

Decimal Notation

x = 1.19258 \dots, x = - 4.19258 \dots

Solution steps

x^{2} + 3 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 5) = 29

x_{1, 2} = \frac{- 3 \pm 29}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 29}{2 \cdot 1}, x_{2} = \frac{- 3 - 29}{2 \cdot 1}

x = \frac{- 3 + 29}{2 \cdot 1} : \frac{- 3 + 29}{2}

x = \frac{- 3 - 29}{2 \cdot 1} : \frac{- 3 - 29}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 29}{2}, x = \frac{- 3 - 29}{2}

3 x^{2} + 2 x = - 9

x (13 + x) + 6 = 42

x^{2} + 4 x + 1 = 0

6 x = x^{2} - 27

3 x^{2} - 12 x + 27 = 0

What are the solutions to the equation solvefor x,x^2+3x-5=0 ?
The solutions to the equation solvefor x,x^2+3x-5=0 are x=(-3+sqrt(29))/2 ,x=(-3-sqrt(29))/2
Find the zeros of solvefor x,x^2+3x-5=0
The zeros of solvefor x,x^2+3x-5=0 are x=(-3+sqrt(29))/2 ,x=(-3-sqrt(29))/2