What are the solutions to the equation 20x^2+5x-11=0 ?

The solutions to the equation 20x^2+5x-11=0 are x=(-5+sqrt(905))/(40),x=(-5-sqrt(905))/(40)

Find the zeros of 20x^2+5x-11=0

The zeros of 20x^2+5x-11=0 are x=(-5+sqrt(905))/(40),x=(-5-sqrt(905))/(40)

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20 x^{2} + 5 x - 11 = 0

x = \frac{- 5 + 905}{40}, x = \frac{- 5 - 905}{40}

Decimal Notation

x = 0.62708 \dots, x = - 0.87708 \dots

Solution steps

20 x^{2} + 5 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 20 ( - 11 )}{2 \cdot 20}

5^{2} - 4 \cdot 20 (- 11) = 905

x_{1, 2} = \frac{- 5 \pm 905}{2 \cdot 20}

Separate the solutions

x_{1} = \frac{- 5 + 905}{2 \cdot 20}, x_{2} = \frac{- 5 - 905}{2 \cdot 20}

x = \frac{- 5 + 905}{2 \cdot 20} : \frac{- 5 + 905}{40}

x = \frac{- 5 - 905}{2 \cdot 20} : \frac{- 5 - 905}{40}

The solutions to the quadratic equation are:

x = \frac{- 5 + 905}{40}, x = \frac{- 5 - 905}{40}

x^{2} + 2 x + 1 = 64

- x^{2} + 2 x + 7 = 0

\frac{x ^{2}}{3} - \frac{x ( x - 1 )}{4} - 1 = (x^{2} - 1)

3 x^{2} - 1 = 4 λ x, - y = 2 λ x, x^{2} + y^{2} = 1

2 a x^{2} + (3 a - 1) x + a + b = 0

What are the solutions to the equation 20x^2+5x-11=0 ?
The solutions to the equation 20x^2+5x-11=0 are x=(-5+sqrt(905))/(40),x=(-5-sqrt(905))/(40)
Find the zeros of 20x^2+5x-11=0
The zeros of 20x^2+5x-11=0 are x=(-5+sqrt(905))/(40),x=(-5-sqrt(905))/(40)