What are the solutions to the equation x^2-14x+49=12 ?

The solutions to the equation x^2-14x+49=12 are x=7+2sqrt(3),x=7-2sqrt(3)

Find the zeros of x^2-14x+49=12

The zeros of x^2-14x+49=12 are x=7+2sqrt(3),x=7-2sqrt(3)

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x^{2} - 14 x + 49 = 12

x = 7 + 23, x = 7 - 23

Decimal Notation

x = 10.46410 \dots, x = 3.53589 \dots

Solution steps

x^{2} - 14 x + 49 = 12

Move

12

to the left side

x^{2} - 14 x + 37 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 37}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 37 = 43

x_{1, 2} = \frac{- ( - 14 ) \pm 4 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 4 3}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 4 3}{2 \cdot 1}

x = \frac{- ( - 14 ) + 4 3}{2 \cdot 1} : 7 + 23

x = \frac{- ( - 14 ) - 4 3}{2 \cdot 1} : 7 - 23

The solutions to the quadratic equation are:

x = 7 + 23, x = 7 - 23

- 4 x^{2} + 12 x + 9 = 0

- 2 x^{2} + 4 x + 30 = 0

x^{2} + 2 x^{2} - x - 2 = 0

2 x^{2} + 2 x - x - 1 = 0

\frac{n ( 3 n + 1 )}{2} = 200

What are the solutions to the equation x^2-14x+49=12 ?
The solutions to the equation x^2-14x+49=12 are x=7+2sqrt(3),x=7-2sqrt(3)
Find the zeros of x^2-14x+49=12
The zeros of x^2-14x+49=12 are x=7+2sqrt(3),x=7-2sqrt(3)