What are the solutions to the equation (x-3)^2-2=0 ?

The solutions to the equation (x-3)^2-2=0 are x=sqrt(2)+3,x=-sqrt(2)+3

Find the zeros of (x-3)^2-2=0

The zeros of (x-3)^2-2=0 are x=sqrt(2)+3,x=-sqrt(2)+3

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(x - 3)^{2} - 2 = 0

x = 2 + 3, x = - 2 + 3

Decimal Notation

x = 4.41421 \dots, x = 1.58578 \dots

Solution steps

(x - 3)^{2} - 2 = 0

Move

2

to the right side

(x - 3)^{2} = 2

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 2 : x = 2 + 3

Solve

x - 3 = - 2 : x = - 2 + 3

The solutions to the quadratic equation are:

x = 2 + 3, x = - 2 + 3

5 x^{2} - 14 x = 3

x (x + 4) = - 3

(3 k + 2)^{2} = 49

x, 615 + x^{2} = 2^{y}

2 x^{2} + 11 x - 15 = 0

What are the solutions to the equation (x-3)^2-2=0 ?
The solutions to the equation (x-3)^2-2=0 are x=sqrt(2)+3,x=-sqrt(2)+3
Find the zeros of (x-3)^2-2=0
The zeros of (x-3)^2-2=0 are x=sqrt(2)+3,x=-sqrt(2)+3