What are the solutions to the equation -0.6x^2+6x+2=0 ?

The solutions to the equation -0.6x^2+6x+2=0 are x=-(-15+sqrt(255))/3 ,x=(15+sqrt(255))/3

Find the zeros of -0.6x^2+6x+2=0

The zeros of -0.6x^2+6x+2=0 are x=-(-15+sqrt(255))/3 ,x=(15+sqrt(255))/3

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- 0.6 x^{2} + 6 x + 2 = 0

x = - \frac{- 15 + 255}{3}, x = \frac{15 + 255}{3}

Decimal Notation

x = - 0.32290 \dots, x = 10.32290 \dots

Solution steps

- 0.6 x^{2} + 6 x + 2 = 0

Multiply both sides by

10

- 6 x^{2} + 60 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 60 \pm 6 0 ^{2} - 4 ( - 6 ) \cdot 20}{2 ( - 6 )}

6 0^{2} - 4 (- 6) \cdot 20 = 4255

x_{1, 2} = \frac{- 60 \pm 4 255}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- 60 + 4 255}{2 ( - 6 )}, x_{2} = \frac{- 60 - 4 255}{2 ( - 6 )}

x = \frac{- 60 + 4 255}{2 ( - 6 )} : - \frac{- 15 + 255}{3}

x = \frac{- 60 - 4 255}{2 ( - 6 )} : \frac{15 + 255}{3}

The solutions to the quadratic equation are:

x = - \frac{- 15 + 255}{3}, x = \frac{15 + 255}{3}

9 x^{2} + 15 x + 4 = 0

7 - 8 x = 6 x + 5 x^{2}

x, y = 4 x^{2}

2 r^{2} + 2 r + 6 = 0

- x^{2} - 6 x - 4 = 0

What are the solutions to the equation -0.6x^2+6x+2=0 ?
The solutions to the equation -0.6x^2+6x+2=0 are x=-(-15+sqrt(255))/3 ,x=(15+sqrt(255))/3
Find the zeros of -0.6x^2+6x+2=0
The zeros of -0.6x^2+6x+2=0 are x=-(-15+sqrt(255))/3 ,x=(15+sqrt(255))/3