What are the solutions to the equation 2r^2+2r+6=0 ?

The solutions to the equation 2r^2+2r+6=0 are r=-1/2+i(sqrt(11))/2 ,r=-1/2-i(sqrt(11))/2

Find the zeros of 2r^2+2r+6=0

The zeros of 2r^2+2r+6=0 are r=-1/2+i(sqrt(11))/2 ,r=-1/2-i(sqrt(11))/2

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2 r^{2} + 2 r + 6 = 0

r = - \frac{1}{2} + i \frac{11}{2}, r = - \frac{1}{2} - i \frac{11}{2}

Solution steps

2 r^{2} + 2 r + 6 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

Simplify

2^{2} - 4 \cdot 2 \cdot 6 : 211 i

r_{1, 2} = \frac{- 2 \pm 2 11 i}{2 \cdot 2}

Separate the solutions

r_{1} = \frac{- 2 + 2 11 i}{2 \cdot 2}, r_{2} = \frac{- 2 - 2 11 i}{2 \cdot 2}

r = \frac{- 2 + 2 11 i}{2 \cdot 2} : - \frac{1}{2} + i \frac{11}{2}

r = \frac{- 2 - 2 11 i}{2 \cdot 2} : - \frac{1}{2} - i \frac{11}{2}

The solutions to the quadratic equation are:

r = - \frac{1}{2} + i \frac{11}{2}, r = - \frac{1}{2} - i \frac{11}{2}

- x^{2} - 6 x - 4 = 0

4 x^{2} = 6 x + 28

X^{2} = 64

3.5 y^{2} - 0.1 y - 0.6 = 0

3 x^{2} - x + 5 = 7

What are the solutions to the equation 2r^2+2r+6=0 ?
The solutions to the equation 2r^2+2r+6=0 are r=-1/2+i(sqrt(11))/2 ,r=-1/2-i(sqrt(11))/2
Find the zeros of 2r^2+2r+6=0
The zeros of 2r^2+2r+6=0 are r=-1/2+i(sqrt(11))/2 ,r=-1/2-i(sqrt(11))/2