What are the solutions to the equation x^2+8x=38 ?

The solutions to the equation x^2+8x=38 are x=-4+3sqrt(6),x=-4-3sqrt(6)

Find the zeros of x^2+8x=38

The zeros of x^2+8x=38 are x=-4+3sqrt(6),x=-4-3sqrt(6)

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x^{2} + 8 x = 38

x = - 4 + 36, x = - 4 - 36

Decimal Notation

x = 3.34846 \dots, x = - 11.34846 \dots

Solution steps

x^{2} + 8 x = 38

Move

38

to the left side

x^{2} + 8 x - 38 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 38 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 38) = 66

x_{1, 2} = \frac{- 8 \pm 6 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 6 6}{2 \cdot 1}, x_{2} = \frac{- 8 - 6 6}{2 \cdot 1}

x = \frac{- 8 + 6 6}{2 \cdot 1} : - 4 + 36

x = \frac{- 8 - 6 6}{2 \cdot 1} : - 4 - 36

The solutions to the quadratic equation are:

x = - 4 + 36, x = - 4 - 36

x, 2 x^{2} + 4 x - 7 = 0

x^{2} + 8 x = - 8

- x^{2} - 10 x + 2000 = 0

x, 15 x^{2} - 4 y^{2} + 15 z^{2} = - 4

x^{2} + 2 x = \frac{1}{4}

What are the solutions to the equation x^2+8x=38 ?
The solutions to the equation x^2+8x=38 are x=-4+3sqrt(6),x=-4-3sqrt(6)
Find the zeros of x^2+8x=38
The zeros of x^2+8x=38 are x=-4+3sqrt(6),x=-4-3sqrt(6)