What are the solutions to the equation x^2+8x=-8 ?

The solutions to the equation x^2+8x=-8 are x=2(sqrt(2)-2),x=-2(2+sqrt(2))

Find the zeros of x^2+8x=-8

The zeros of x^2+8x=-8 are x=2(sqrt(2)-2),x=-2(2+sqrt(2))

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x^{2} + 8 x = - 8

x = 2 (2 - 2), x = - 2 (2 + 2)

Decimal Notation

x = - 1.17157 \dots, x = - 6.82842 \dots

Solution steps

x^{2} + 8 x = - 8

Move

8

to the left side

x^{2} + 8 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 8 = 42

x_{1, 2} = \frac{- 8 \pm 4 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 4 2}{2 \cdot 1}, x_{2} = \frac{- 8 - 4 2}{2 \cdot 1}

x = \frac{- 8 + 4 2}{2 \cdot 1} : 2 (2 - 2)

x = \frac{- 8 - 4 2}{2 \cdot 1} : - 2 (2 + 2)

The solutions to the quadratic equation are:

x = 2 (2 - 2), x = - 2 (2 + 2)

- x^{2} - 10 x + 2000 = 0

x, 15 x^{2} - 4 y^{2} + 15 z^{2} = - 4

x^{2} + 2 x = \frac{1}{4}

6 x^{2} + 9 x - 27 = 0

X^{2} + 2 X + 2 = 0

What are the solutions to the equation x^2+8x=-8 ?
The solutions to the equation x^2+8x=-8 are x=2(sqrt(2)-2),x=-2(2+sqrt(2))
Find the zeros of x^2+8x=-8
The zeros of x^2+8x=-8 are x=2(sqrt(2)-2),x=-2(2+sqrt(2))