What are the solutions to the equation x^2+2x= 1/4 ?

The solutions to the equation x^2+2x= 1/4 are x=(-2+sqrt(5))/2 ,x=-(2+sqrt(5))/2

Find the zeros of x^2+2x= 1/4

The zeros of x^2+2x= 1/4 are x=(-2+sqrt(5))/2 ,x=-(2+sqrt(5))/2

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x^{2} + 2 x = \frac{1}{4}

x = \frac{- 2 + 5}{2}, x = - \frac{2 + 5}{2}

Decimal Notation

x = 0.11803 \dots, x = - 2.11803 \dots

Solution steps

x^{2} + 2 x = \frac{1}{4}

Multiply both sides by

4

4 x^{2} + 8 x = 1

Move

1

to the left side

4 x^{2} + 8 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 4 ( - 1 )}{2 \cdot 4}

8^{2} - 4 \cdot 4 (- 1) = 45

x_{1, 2} = \frac{- 8 \pm 4 5}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 8 + 4 5}{2 \cdot 4}, x_{2} = \frac{- 8 - 4 5}{2 \cdot 4}

x = \frac{- 8 + 4 5}{2 \cdot 4} : \frac{- 2 + 5}{2}

x = \frac{- 8 - 4 5}{2 \cdot 4} : - \frac{2 + 5}{2}

The solutions to the quadratic equation are:

x = \frac{- 2 + 5}{2}, x = - \frac{2 + 5}{2}

6 x^{2} + 9 x - 27 = 0

X^{2} + 2 X + 2 = 0

x^{2} + 7 x + 10 = 0

x, \frac{( x ^{2} + y ^{3} )}{y} - 4 x^{2} y = 4

- 7 x + 6 = - 4 x^{2}

What are the solutions to the equation x^2+2x= 1/4 ?
The solutions to the equation x^2+2x= 1/4 are x=(-2+sqrt(5))/2 ,x=-(2+sqrt(5))/2
Find the zeros of x^2+2x= 1/4
The zeros of x^2+2x= 1/4 are x=(-2+sqrt(5))/2 ,x=-(2+sqrt(5))/2