What are the solutions to the equation 6x^2+9x-27=0 ?

The solutions to the equation 6x^2+9x-27=0 are x= 3/2 ,x=-3

Find the zeros of 6x^2+9x-27=0

The zeros of 6x^2+9x-27=0 are x= 3/2 ,x=-3

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6 x^{2} + 9 x - 27 = 0

x = \frac{3}{2}, x = - 3

Decimal Notation

x = 1.5, x = - 3

Solution steps

6 x^{2} + 9 x - 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 6 ( - 27 )}{2 \cdot 6}

9^{2} - 4 \cdot 6 (- 27) = 27

x_{1, 2} = \frac{- 9 \pm 27}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 9 + 27}{2 \cdot 6}, x_{2} = \frac{- 9 - 27}{2 \cdot 6}

x = \frac{- 9 + 27}{2 \cdot 6} : \frac{3}{2}

x = \frac{- 9 - 27}{2 \cdot 6} : - 3

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - 3

X^{2} + 2 X + 2 = 0

x^{2} + 7 x + 10 = 0

x, \frac{( x ^{2} + y ^{3} )}{y} - 4 x^{2} y = 4

- 7 x + 6 = - 4 x^{2}

- 5 - 7 + 1 x - 3 - 1 x^{2} + 6 x^{2} = - 5 x + 4 x + 4 x^{2}

What are the solutions to the equation 6x^2+9x-27=0 ?
The solutions to the equation 6x^2+9x-27=0 are x= 3/2 ,x=-3
Find the zeros of 6x^2+9x-27=0
The zeros of 6x^2+9x-27=0 are x= 3/2 ,x=-3