What are the solutions to the equation λ^2+6λ+5=0 ?

The solutions to the equation λ^2+6λ+5=0 are λ=-1,λ=-5

Find the zeros of λ^2+6λ+5=0

The zeros of λ^2+6λ+5=0 are λ=-1,λ=-5

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λ^{2} + 6 λ + 5 = 0

λ = - 1, λ = - 5

Solution steps

λ^{2} + 6 λ + 5 = 0

Solve with the quadratic formula

λ_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 5 = 4

λ_{1, 2} = \frac{- 6 \pm 4}{2 \cdot 1}

Separate the solutions

λ_{1} = \frac{- 6 + 4}{2 \cdot 1}, λ_{2} = \frac{- 6 - 4}{2 \cdot 1}

λ = \frac{- 6 + 4}{2 \cdot 1} : - 1

λ = \frac{- 6 - 4}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

λ = - 1, λ = - 5

x^{2} - 7 = - 14

x^{2} - 7 = - 12

s^{2} - 4 s - 4 = 0

x^{2} + 192 = 0

y, y^{2} + z^{2} = 0

What are the solutions to the equation λ^2+6λ+5=0 ?
The solutions to the equation λ^2+6λ+5=0 are λ=-1,λ=-5
Find the zeros of λ^2+6λ+5=0
The zeros of λ^2+6λ+5=0 are λ=-1,λ=-5