What are the solutions to the equation 2p^2-10p+9=0 ?

The solutions to the equation 2p^2-10p+9=0 are p=(5+sqrt(7))/2 ,p=(5-sqrt(7))/2

Find the zeros of 2p^2-10p+9=0

The zeros of 2p^2-10p+9=0 are p=(5+sqrt(7))/2 ,p=(5-sqrt(7))/2

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2 p^{2} - 10 p + 9 = 0

p = \frac{5 + 7}{2}, p = \frac{5 - 7}{2}

Decimal Notation

p = 3.82287 \dots, p = 1.17712 \dots

Solution steps

2 p^{2} - 10 p + 9 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 2 \cdot 9}{2 \cdot 2}

(- 10)^{2} - 4 \cdot 2 \cdot 9 = 27

p_{1, 2} = \frac{- ( - 10 ) \pm 2 7}{2 \cdot 2}

Separate the solutions

p_{1} = \frac{- ( - 10 ) + 2 7}{2 \cdot 2}, p_{2} = \frac{- ( - 10 ) - 2 7}{2 \cdot 2}

p = \frac{- ( - 10 ) + 2 7}{2 \cdot 2} : \frac{5 + 7}{2}

p = \frac{- ( - 10 ) - 2 7}{2 \cdot 2} : \frac{5 - 7}{2}

The solutions to the quadratic equation are:

p = \frac{5 + 7}{2}, p = \frac{5 - 7}{2}

x, x = \frac{200 \cdot 0.07 \cdot 2 ^{2} \cdot ( 1 - x ) ^{2}}{5}

9 - 4 x^{2} = 0

m^{2} - 4 m - 4 = 0

3 p^{2} + 1 = - 43

2 x^{2} - x

What are the solutions to the equation 2p^2-10p+9=0 ?
The solutions to the equation 2p^2-10p+9=0 are p=(5+sqrt(7))/2 ,p=(5-sqrt(7))/2
Find the zeros of 2p^2-10p+9=0
The zeros of 2p^2-10p+9=0 are p=(5+sqrt(7))/2 ,p=(5-sqrt(7))/2