What are the solutions to the equation 8x^2+43x=7x ?

The solutions to the equation 8x^2+43x=7x are x=0,x=-9/2

Find the zeros of 8x^2+43x=7x

The zeros of 8x^2+43x=7x are x=0,x=-9/2

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8 x^{2} + 43 x = 7 x

x = 0, x = - \frac{9}{2}

Decimal Notation

x = 0, x = - 4.5

Solution steps

8 x^{2} + 43 x = 7 x

Move

7 x

to the left side

8 x^{2} + 36 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 \cdot 8 \cdot 0}{2 \cdot 8}

3 6^{2} - 4 \cdot 8 \cdot 0 = 36

x_{1, 2} = \frac{- 36 \pm 36}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 36 + 36}{2 \cdot 8}, x_{2} = \frac{- 36 - 36}{2 \cdot 8}

x = \frac{- 36 + 36}{2 \cdot 8} : 0

x = \frac{- 36 - 36}{2 \cdot 8} : - \frac{9}{2}

The solutions to the quadratic equation are:

x = 0, x = - \frac{9}{2}

2 y^{2} + 8 y

15 x^{2} - 3 x = 0

25 p^{2} + 70 p + 49 = 0

- 0.2 x^{2} + 1.6 x

m^{2} = 4 m - 3

What are the solutions to the equation 8x^2+43x=7x ?
The solutions to the equation 8x^2+43x=7x are x=0,x=-9/2
Find the zeros of 8x^2+43x=7x
The zeros of 8x^2+43x=7x are x=0,x=-9/2